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Tuesday, September 16, 2008

Kiln Dilemma

Discovered a bit about electricity over the weekend.
I was standing in front of the electric kiln and my thoughts were: Hmmm . . . how can i make you work?
Or more to the point: Why aren't you working?

OK. Some people talk to their kilns and others do not. Me? I'm a quasi-talker. If there's a possibility of building a harmonious relationship with the mechanical beasti -- i talk, conjole, threaten, plead . . .
If it's an alien from an unknown universe who will never understand the linguistics, silence is the ticket.
Kilns fall somewhere's in the realm of in-between.

Now my Paragon Electric Kiln has done its best to co-operate with me. But, then again, in the other house it had a 20-amp dedicated circuit. That is not the case here.
But i am here and how am i gonna make this thing work?
Knowing that all the garage recepticals are wired to the same circuit, i turned the breaker off to see what else was wired to the same circuit.
Discovered the 2 ceiling lights went off when the breaker was tripped. That's 1.66 amps right there. The kiln draws 19 amps. OK. So we're over the 20 amp breaker limit ! Worse yet, the garage-door opener is wired to the same circuit. It draws 6 amps.
If you consider that a 20-amp wire can carry 20 amps all day long but that the breakers can only carry 80 percent of their rating on a continuous basis (which is a circuit loaded to capacity for 3 hours or more) we now have a reasonable defination of why the Paragon kiln will not reach Cone 6 temperatures in this house on the garage circuit.

Thought maybe if i did the math and transposed everything to watts, i'd get a different answer. But nope. That didn't work either. It just provided a definate answer that this situation, as it is, isn't going to work.
Intriguingly tho, the face-plate on the kiln reads: usage: 19 amps and 2200 watts. Those 2200 watts read out as 18.33 amps when the calculation is applied. What gives with that? The kiln either uses 19 amps or 18.33 amps . . . . but certainly not both as the wattage vs the amperage indicate.
It's a moot point however, for in either case the amount is over the maximum load of the circuit.

Ah sure now, it's back to the drawing board. But in this house -- i'm gonna have to find the drawing board before i can make furthering calculations . . . .

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